Gauss Seidel Program In Scilab

Gauss Seidel Program In Scilab Rating: 7,1/10 4153 votes

Use Jacobi and Gauss Seidel iterative methods Learn how to iterate until we converge at the solution Learn how Gauss Seidel method is faster than Jacobi method Develop Scilab code for these two methods to solve linear equations Numerical methods- Interpolation. Develop Scilab code for different Numerical Interpolation algorithms. Academia.edu is a platform for academics to share research papers.

Gauss elimination and Gauss Jordan methods using MATLAB code
gauss.m
% Code from 'Gauss elimination and Gauss Jordan methods using MATLAB'
% https://www.youtube.com/watch?v=kMApKEKisKE
a = [34 -222
49 -358
-2 -37610
14672];
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%Gauss elimination method [m,n)=size(a);
[m,n]=size(a);
for j=1:m-1
for z=2:m
if a(j,j)0
t=a(j,:);a(j,:)=a(z,:);
a(z,:)=t;
end
end
for i=j+1:m
a(i,:)=a(i,:)-a(j,:)*(a(i,j)/a(j,j));
end
end
x=zeros(1,m);
for s=m:-1:1
c=0;
for k=2:m
c=c+a(s,k)*x(k);
end
x(s)=(a(s,n)-c)/a(s,s);
end
disp('Gauss elimination method:');
a
x'
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% Gauss-Jordan method
[m,n]=size(a);
for j=1:m-1
for z=2:m
if a(j,j)0
t=a(1,:);a(1,:)=a(z,:);
a(z,:)=t;
end
end
for i=j+1:m
a(i,:)=a(i,:)-a(j,:)*(a(i,j)/a(j,j));
end
end
for j=m:-1:2
for i=j-1:-1:1
a(i,:)=a(i,:)-a(j,:)*(a(i,j)/a(j,j));
end
end
for s=1:m
a(s,:)=a(s,:)/a(s,s);
x(s)=a(s,n);
end
disp('Gauss-Jordan method:');
a
x'

commented Mar 25, 2015

what is the difference bw gauss Jordan method and gauss Jordan elimination

commented Sep 8, 2016•
edited

in line 14 , it will be
for z=j+1:m
otherwise
for z=2:m
will not work for
a=[2 1 -1 2 5
4 5 -3 6 9
4 2 -2 9 8
4 11 -4 8 2];

commented Nov 9, 2016

a(j,:) means?

commented Dec 8, 2016

Can i get the matlab gui implementation of gauss elimination ?

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commented Dec 19, 2016

Good job

commented Apr 26, 2018

if your matrix is changed as shown below, does your program work?

a = [3 4 -2 2 2
4 0 -3 5 8
-2 -3 0 6 10
1 4 6 7 2];
thanks

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commented Dec 20, 2018•
edited

commented Feb 14, 2019•
edited

Can we find inverse using this method ? What is the final output which we get ?

commented Mar 16, 2019

good job

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